$y\frac{x-6}{3x-3}$
$\int\frac{x+1}{\left(x-3\right)\left(x^2+2x+2\right)}dx$
$\frac{3}{\left(1+2x\right)^2}$
$1+19a^2-14a$
$\int\left(ln\left(16x\right)\right)^2dx$
$\frac{dy}{dx}=-\frac{1}{4y^3}$
$x^2-x+5=0$
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