$\left(\frac{1}{3}+x^3\right)\cdot\left(\frac{1}{3}-x^2\right)$
$cos\left(x\right)=sec\left(x\right)-sec\left(x\right)\left(sin\left(x\right)\right)^2$
$\frac{8m}{2m}^3+\frac{n^3}{n}$
$x\left(2\right)-\:14x+k$
$4x-x^2-9$
$-13-3\cdot2$
$36x^2-2\left(6x\right)-y^4$
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