$\frac{dy}{dx}=10xe^{5y}$
$y=\frac{4x^4-2x^8}{3x^{10}}$
$\arcsin\left(\frac{\frac{\infty}{2}}{\left(5^2+\frac{\infty\:}{2}^2\right)^{\frac{1}{2}}}\right)$
$\int\left(3x^2\sqrt[4]{8+2x^3}\right)dx$
$y=\frac{3x-x^2}{x+2}$
$x^2+12x-13=0$
$y'=2xe^y$
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