$3y^{\frac{1}{\:3}}+c=x+c$
$-2+3\:-3.x^2\:+\:4.x^3$
$dy-cy-kdx=0$
$3-1+2+1-7$
$4+7x^2-4x$
$\sqrt[1]{-25}$
$-12-\left(-3\right)-\left(-15\right)$
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