$\frac{639}{-9}$
$\lim_{x\to\infty}\left(3+\frac{5}{x}\right)^{-2x+4}$
$13.5\cdot13.5$
$\frac{x^3-5x^2-43x-25}{x+4}$
$\int\frac{\sqrt{9x^2+16}}{x}dx$
$\frac{x^2+5x}{-x^2-3x+3}$
$-\left(-5\right)-\left(-9\right)\cdot\left(-4\right)$
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