$\left(-6-4\right)\cdot3$
$x^2+12x-24=0$
$\sqrt[3]{9a^6b^{12}}$
$\:\frac{sec\left(x\right)}{cos\left(x\right)}-1$
$15\cdot1500$
$\left(x^2-xy+y^2\right)\left(3x-y\right)$
$x-6=8$
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