$4a^2-\left(1-a\right)^2$

$\int\left(6y+4t-1\right)dy$

$7x-11<2x+160$

$-2\:\frac{3}{4}-3\:\frac{5}{6}$

$2^2-x^2$

$\frac{\left(1-sin\left(t\right)\right)}{cos^2\left(t\right)}+\frac{1}{1-sin\left(t\right)}$

$\frac{d}{dx}\left(\left(\ln\:\left(xy+1\right)\right)^2=y\right)$