$\frac{dx}{dt}=-2x$
$\int ln\:\left(2x+1\right)\:dx$
$\int_1^{\infty}\left(\frac{x\ln\left(x\right)}{\left(1+x^2\right)^2}\right)dx$
$3w=9$
$\frac{\frac{sina}{cosa}}{\frac{1}{cosa}}$
$\frac{6}{x}+\frac{3}{x^2}=\frac{9}{x}$
$\frac{x}{x+1};\:x=1$
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