$\int_{-\infty}^0\left(\frac{1}{\left(2x-5\right)}\right)dx$
$3x-2=5x+16$
$\left(a-1\right)^5$
$\frac{\left(3x^2-2x\right)}{\left(3x+2\right)}<-2$
$\sqrt{-32}$
$\left[\left(-5+3\right)-\left(-1+2\right)\right]-\left(2-5\right)$
$6z^3+12z^2+10z$
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