$\sin\left(x\right)^2\cdot\sec\left(x\right)^2=\tan\left(x\right)^2$
$4-4a-a^2$
$xy^2=0$
$\left(f+g\right)\left(3\right)$
$\left[5-7.\left(-3\right)-\left(5-3\right)\right]$
$\frac{1}{m-n}+\frac{2}{m+n}+\frac{2m}{m^2-mn+n^2}$
$-\frac{2}{8z^4}$
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