$3x^2-18x+6$
$\frac{2x^45x^3-2x-8}{x+3}$
$\lim_{x\to0}\left(\frac{6\cos\left(x\right)}{x^2}\right)$
$\frac{d}{dx}\left(\left(x-4\sqrt{x}\right)\right)$
$\sin^2\:a=1-\frac{\cot^2}{\csc^2}$
$-3\:-\:\left(-2\right)$
$sin\:t=\frac{2}{3}$
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