$sin^4x=cos^4$
$\frac{4x^2-40x^2-5x+25}{x+3}$
$-8x+5=-11$
$2\sqrt[4]{x}+5=7$
$\frac{1}{3}\int\left(\frac{1}{\tan\left(x\right)}\right)dx$
$\left(10x^2+3xy^5\right)^2$
$\left(-2s^2\:+\:4s\:-\:10\right)$
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