$\frac{10x^{11}y^{11}}{9x^7y^8}$
$\:14\:x^3\:y^4\:z^5\:entre\:7\:x^2\:y^3\:z\:$
$-\int\:2xdx$
$10\cdot 57$
$\left(a^4b^2-c^3\right)^2$
$x^2+10x-5$
$\frac{6\left(x-3\right)}{3}=\frac{2\left(x+4\right)}{8}$
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