$\int\frac{\left(x\right)}{\sqrt{1-2x^2}}dx$
$\left(-\frac{2b^6}{5}\right)^2$
$4c+5c$
$\frac{-1\sin\left(x\right)-1\sin\left(x\right)\tan^{2}\left(x\right)}{\sec^{2}\left(x\right)}$
$a-bcosx=y$
$-15+-26+\:17$
$6\cdot x-8\cdot y\sqrt{x^2+1}\:\frac{dy}{dx}=0$
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