$\frac{dy}{dt}-3y=e^{2t}$
$\int t^2\:dx$
$\left(a^{\frac{1}{2}}+5\right)\left(a^{\frac{1}{2}}+8\right)$
$\left(4a^6+b^2\right)^2$
$16g+10-4g$
$2x-1=-7$
$1\:.\:1\:.\:0,0016$
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