$-3x\sin\left(x\right)+3x^2$
$\left(w^3+3w-5\right)\left(-4\right)$
$\frac{1}{2}x^{2\:}-5x=17$
$\int x\left(2x^2-8\right)dx$
$\int\frac{2r^2}{r^4-9r^3+27r^2-27r}ds$
$4x^2+4x+16$
$\sqrt{8}-\sqrt{8}$
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