$\left(4x\:+\:3\right)\left(6x\:-1\right)=9-34x$
$\int\frac{6x^2+12x-18}{\left(x-1\right)^2}dx$
$\int3x\cdot\cos\left(nx\right)dx$
$\int\:\left(-13\right)x^2e^{9x^3+\left(-93\right)}dx$
$5\left(x-3\right)=15$
$12u^2-8u-15$
$\ln4x^3$
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