$\int tan^2\left(6x+2\right)sec^2\left(6x+2\right)dx$
$\int_0^3\:2t\:dt$
$\left(-2\right)\:x\:\left(0\right)$
$y-3>-9$
$-2-3+4+8+5$
$-\left(-1\right)+\left(-7\right)$
$4-18-12$
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