$\int\frac{\left(3x\right)}{\left(2x+1\right)^5}dx$

$\left(2x^4y^0\right)^2$

$\frac{2\tan\left(x\right)}{\sec\left(x\right)}$

$\int\frac{2}{\left(x+1\right)^2+2}dx$

$\left(-2\right)\left(-1\right)\left(-3\right)\left(-4\right)\left(-1\right)$

$14x^2-21x+6x-9$

$4^{\left(12-4x\right)}=256$