$y=\frac{x^5}{x^4-1}$
$y\cdot\frac{dy}{dx}=-4\cdot x^2$
$\int\frac{2x^3+10x}{x\left(x+1\right)^2}dx$
$\int\frac{x\:e^x}{3}dx$
$y=3\ln\left(\sin^2\left(x\right)\right)$
$ydy=7xdx$
$\left(\frac{7}{4}x-5\right)\:\left(\frac{7}{4}x-1\right)$
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