$\frac{dy}{1+y^2}=\left(1+x\right)dx$
$\int\frac{8}{\left(y^2-16\right)}\:dy$
$\left(3+8y^2\right)\left(3-8y^2\right)$
$12-\left(1+5\right)$
$y^2+14y-24$
$4x^3\cdot4x^3$
$cos^5x=\left(1-sin^2x\right)^2cosx$
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