$\lim_{x\to-2}\left(x^4-3x^2+6\right)$
$\left(2r-3a\right)^3$
$x+\frac{1}{x}=\sqrt{7}$
$\left(-m-25\right)\left(_{-m+25}\right)$
$\left(4x-6\right)\left(4x-2\right)$
$\cos\left(\theta\:\right)=\:\frac{8}{17}$
$x^2-12x+59=0$
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