$\lim_{x\to0}\left(\frac{cos3x}{sin3x}\right)$
$x^2-8x=9$
$\left(p+3\right)\left(p-4\right)$
$\frac{dy}{dx}\left(x^2\:+\:7\:x\:+2\right)\left(2\:x^2\:+4\right)$
$-6x^2+12x-20$
$-10n+20+2n+6$
$\frac{x^3+6x+3}{2x-2x+2}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!