$m^{-\frac{4}{5}}$
$3x^2-6+2x\ge0$
$\int\left(s^{\frac{3}{5}}cos\left(s^{\frac{8}{5}}+6\right)\right)ds$
$4\left(2x-5\right)=x+1$
$\left(-1+9\right)^n$
$cos^2\left(a\right)=sen^2\left(a\right)cos^2\left(a\right)+cos^4\left(a\right)$
$\left(2a^3-5\right)^3$
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