$\left(2+x\right)\:\frac{dy}{dx}\:=\:3y$
$\frac{dy}{dx}\left(lnx+lny^2=3\right)$
$x+y-2x-2y$
$\frac{x}{8}+5=6\:\frac{1}{8}$
$\left(4\right)^3\left(4\right)^2\left(4\right)^5$
$\int\left(\frac{3}{\left(3x+7\right)^2}\right)dx$
$x^2-5<x$
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