$\int x\left(x^2+3\right)^{12}dx$
$9x+6y+9z$
$\lim_{x\to\infty}\:\frac{1^{x+1}}{1^x}$
$\int\frac{4x+9}{\left(8x^2+36x\right)^5}dx$
$3m-\frac{2}{5}n+5m-7n+5\frac{1}{2}n+3n-\frac{2}{5}x-5n+8x$
$4x-8<x-2$
$\frac { n } { n }$
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