$\left(x^5+3x^4-7x^3+2x^2+8x-1\right)-\left(x+1\right)$
$\lim_{x\to\infty}\left(\frac{4sin\left(4x^7\right)}{-3x}\right)$
$x^2-4x^4$
$9tanx+6=-tan^2x$
$35a-21<-35a+19$
$\frac{dp}{dt}=0.0009p$
$\frac{\left(3x^2+30x-69\right)}{\left(5x-9\right)}=8$
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