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Factor the trinomial $\left(2x^2+5x-7\right)$ of the form $ax^2+bx+c$, first, make the product of $2$ and $-7$
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$\left(2\right)\left(-7\right)=-14$
Learn how to solve exponential equations problems step by step online. Solve the exponential equation e^x(2x^2+5x+-7)=0. Factor the trinomial \left(2x^2+5x-7\right) of the form ax^2+bx+c, first, make the product of 2 and -7. Now, find two numbers that multiplied give us -14 and add up to 5. Rewrite the original expression. Factor \left(2x^2+7x-2x-7\right) by the greatest common divisor 2.