$0.3\sqrt{40}-2\sqrt{10}$
$9m-4=8m+3$
$x+\frac{2}{x}=4$
$\left(x^2-3y\right)^4$
$x^2+2x-4+0$
$\frac{d}{dx}uv^3$
$\int\frac{\left(8x+9\right)}{\left(4x^2+9x\right)^5}dx$
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