$-\frac{3}{2}x+\frac{5}{6}y-8=2$
$7\left(3x-4\right)+2\left(-6x+5\right)$
$m^4-49n^2$
$\frac{4u^4v^4}{vu^4}$
$\frac{\left(3m^{-1}n^{2}\right)^{4}}{\left(2m^{-2}n\right)^{3}}$
$1+\left|-1-\left(-1\right)\right|$
$x^3+x^2+12x$
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