$\frac{1\left(0\right)^4}{4}-\frac{5\left(0\right)^3}{3}+7\left(0\right)^2+2$
$3x^2-20x-25$
$\frac{120}{107.6}$
$0:\left(-520\right):\left(-73\right)$
$12-\left(+16-11+3\right)$
$-x^2+2x+10=x+4$
$\left(x+11\right)\left(x-10\right)$
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