$\lim_{x\to\infty}16x^2$
$5,201-5,03$
$-9\cdot5\left(-3\right)$
$\int\left(5x^2-8x\right)^5\left(5x-4\right)dx$
$\left(2xy^2-3\right)dx+\left(2x^2y+5\right)dy=0$
$\lim_{x\to\infty}\frac{x}{x^2+6x}.\cos\left(x+5\right)$
$\left(b^3\right)^{-\frac{2}{3}}$
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