$\lim_{x\to-\infty}\:\frac{5^x}{3^x+2^x}$
$\frac{2}{3}x^2-\frac{3}{2}^2$
$\frac{2}{3}a^2+3b$
$3cos2x-1=0$
$\frac{dy}{dx}=-y+e^{-2\cdot x}$
$\:\frac{d}{dx}\left(0=x^2y-y^2\right)$
$e^x+3=\frac{1}{e^2}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!