$\frac{x^3+6x-10}{x+2}$
$5x+6-4y-3+3x-2$
$\left(-6\cdot3-2\cdot6\right)-\left(-1\right)^6$
$3c\ge-30$
$3x+5<4x-2$
$3\left(x+1\right)+6\left(1-x\right)\le\frac{2}{3}$
$\sqrt{784}$
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