$4-7-8-9-3+18$
$x'=3x$
$\left(0\right)x\left(-2\right)$
$-123+\left(-456\right)$
$\left(\frac{b\frac{5}{4}}{a\cdot a^2b\frac{4}{3}}\right)^{\frac{1}{3}}$
$\left(3+\sqrt{y}4\right)\left(3-\sqrt{y}^2\right)^2$
$9q+18=27$
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