$z+6\ge-4$
$\int\frac{x^{2}+1}{x-1}dx$
$\left(\sqrt{2}\cdot\sqrt{3}\right)^4$
$1-\left|0.3\right|$
$27-\left(-14\right)$
$\frac{x^2dy}{dx}+y=0$
$\lim_{x\to\infty}\left(\frac{4\ln\left(x\right)}{x^3}\right)$
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