$\frac{d}{dx}16x^3+9x^2y=54x$
$\frac{d}{dx}\left(3\tan\left(x\right)-\sec\left(x\right)\right)$
$\left(3\right)^4\::\:\left(-3\right)^3$
$\int_{t}^{3}\sentdt$
$\lim_{x\to-\infty}\left(x^3-3x^2\right)$
$\frac{dy}{dx}=\frac{3x^2}{e^y+1}$
$2x^3+x^2-8x-4$
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