$-1\:restar\:-9$
$m^2-8-48$
$\cos\left(3x\right)\:\cos\left(x\right)\:+\:sen3x\:senx$
$\frac{x^2+7x+7}{x-5}$
$6x+10-3x=55$
$15\cdot\left(-25\right)\cdot\left(-4\right)\cdot\left(-10\right)$
$-\left(x+y\right)+\left(3x-3y+\left(-8x-5y-\left(6x-8y-7y\right)\right)-6x\right)$
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