$3x^2+6x-8=0$

$\lim_{x\to\infty}\left(\frac{6x^2-6x^3+6x}{6x-x^2+3x^3}\right)$

$\left(\frac{5}{6}\right)a^2bc+\frac{3}{2}ab^2c^2$

$-10+9ab3-6+ab$

$16a+2016a+20$

$\lim_{x\to2}\left(\frac{5}{x-2}-\frac{3}{x^2-4}\right)$

$\frac{1}{3}\left(a^2+2^2\right)^{\frac{3}{2}}+c$