$\frac{8x^4}{x^2}$
$x^2>=3x-2$
$\int x^2\left(\frac{x^3}{15}+8\right)^4dx$
$1-x<1$
$\int\frac{3x+2}{\left(x+1\right)\left(x+2\right)}dx$
$\int\frac{6}{\left(2x+5\right)^4}dx$
$0,356\cdot3,7$
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