$\int\left(\frac{4}{7+4x}\right)dx$
$x^2-6+9$
$2x^2-3-9$
$x^2+x=12$
$\left(x+0\right)^2=-13$
$\lim_{x\to\infty}\:\frac{1}{x^2}sin\left(x\right)$
$\int12\left(3x+2\right)^3dx$
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