$-6x+12<36$
$\lim_{x\to\infty}\left(\frac{x-4}{x^2+9x+8}\right)$
$\left(2+\left(-1\right)\right)+3\left(3-5\right)$
$a^2-5a-36$
$\left(7x^2+6\right)\left(3x^2-5x+2\right)$
$5y=-7+6y$
$2n+3n+4n-n+9n$
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