$\lim_{x\to\infty}\left(xe^{\frac{6}{x}}\right)$

$\left(16m^2n^7p^4\right)^2$

$\lim_{x\to0}\left(\frac{\sin^2\left(x\right)}{\sin\left(x^2\right)}\right)$

$5x+4<-6$

$8x^2y^5+32x^2y^2-16xy^2$

$-2\left(2\right)-|-4|-\sqrt[3]{-4\left(2\right)}$

$\lim_{x\to0}\left(1+\frac{1}{x}\right)^{2x}$