$x^2+4x+5=0$
$-3x^2+6x+9<0$
$\frac{24}{4}\cdot2+6+2\cdot\left(4+\frac{2^2}{4}-1\right)$
$\lim_{x\to2}\left(\left(x^2+3x-4\right)\right)$
$0.008+0.085$
$\left(2x-6\right)\left(5-x\right)$
$15a^2-30ba$
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