$x'=x\left(1-x\right)\left(2-x\right)$
$\left(7x+5\right)\left(4x-3\right)$
$\frac{14x^4}{16x^3}$
$\left(2c-1\right)\left(c+5\right)$
$cos\left(4x\right)=2\left(2cos^2\left(x\right)-1\right)^2-1$
$i^2+18i+49$
$\left(-4ab^3\right)^3$
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