$\lim_{x\to0}\left(\frac{4x}{\left(x^2+1\right)^2}\right)$
$9\left(-8\right)^2-6\left(-5\right)^2$
$-5+x\cdot x+5$
$4+\left(+3+1\right)$
$9\cdot400$
$x^2-10x+21=0$
$x^3\sqrt[4]{32x^5y^3}$
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