$2x^2-3x^2+4x-6$
$\left(\frac{3}{7}x+\frac{1}{2}\right)\left(\frac{3}{7}x-\frac{1}{2}\right)$
$\left(7x^2-5\right)\left(7x^2-1\right)$
$5+8\left(x+10\right)$
$\frac{dy}{dx}=\left(y+1\right)^{-3}$
$3-3\sin\left(x\right)=6\cos\left(x\right)^2$
$\frac{dy}{dx}=1-x$
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