$x^2+\frac{5}{x}-8$
$\frac{d}{dx}\left(2cos\left(x+2y\right)+sin\left(yz\right)-1\right)=0$
$-7\log_{11}\left(-x-8\right)=-28$
$27+4^3$
$y=\left(\left(2x\right)^{x^2}\right)$
$1.3\cdot10^2$
$y\:dy=2\:12x^2+1dx$
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