$\frac{x^{2}}{36}+\frac{y^{2}}{32}=1$

$\frac{16x^4-81y^2}{4x^2-9y}$

$\frac{3\left(x^2-\frac{4}{5}\right)}{8}+\frac{\left(x^2-\frac{4}{5}\right)}{4}=2$

$\lim_{x\to1}\left(\frac{1}{\ln\left(x\right)}-\frac{1}{x}\right)$

$m^2\:+8m\:+16$

$\left(\frac{1}{x}+z\right)\left(-\frac{1}{x}\right)$

$\lim_{x\to0}\left(\frac{\left(ln\left(x\right)\right)^2}{x^{-2}}\right)$