$\left(-12-3\right)+\left(+6-5\right)-\left(-17+3\right)$
$\left(11x^7y^2\right)\left(3x^7y\right)$
$\frac{r}{16}<1$
$-3x-\left(-3\left(x-4y\right)-4\left(-5x-2y\right)\right)$
$50x+\frac{y}{2};\:x=3;y=600$
$-6\cdot0.03$
$7x=28$
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